Question

A 2.3 kg block is connected by a rope across a 35-cm-diameter, 17 kg pulley. There is no friction in the axle, but there is friction between the rope and the pulley; the rope doesn't slip. Th weight is accelerating upward at 0.89 m/s? What is the tension in the rope on the right side of the pulley?

Answer 1

The tension in the rope on the right side of the pulley is 150.66 N.

Step-by-step explanation:

To find the tension in the rope on the right side of the pulley, we can use Newton's second law of motion. The acceleration of the system can be found using the equation:

acceleration = (m2 * g - m1 * g) / (m1 + m2)

where m1 = mass of the block, m2 = mass of the pulley, and g = acceleration due to gravity. Plugging in the values, we get:

acceleration = (17kg * 9.8m/s^2 - 2.3kg * 9.8m/s^2) / (2.3kg + 17kg) = 0.98m/s^2

The tension in the rope can be found using the equation:

tension = m2 * (g - acceleration)

Plugging in the values, we get:

tension = 17kg * (9.8m/s^2 - 0.98m/s^2) = 150.66 N