143k views
4 votes
Construct a line perpendicular to m through P. Then find the distance from P to m. Line m contains points (3, -3) and (0, 0). Point P has coordinates (1, 2).

User Vbstb
by
8.4k points

1 Answer

7 votes

Final answer:

To construct a line perpendicular to line m through point P, find the slope of line m and then find the negative reciprocal of that slope. The equation of the line perpendicular to m through P is y - y1 = m' * (x - x1), and the distance from P to m is 3 / sqrt(2).

Step-by-step explanation:

To construct a line perpendicular to m through point P, we need to find the slope of line m and then find the negative reciprocal of that slope.

First, let's find the slope of line m using the coordinates of two points on the line:

m = (y2 - y1) / (x2 - x1) = (0 - (-3)) / (3 - 0) = 3 / 3 = 1.

So the slope of line m is 1.

Now, to find the slope of the line perpendicular to m, we take the negative reciprocal of 1, which is -1.

The equation of the line perpendicular to m through point P is y - y1 = m' * (x - x1), where m' is the slope of the perpendicular line.

Plugging in the values for point P, we get y - 2 = -1 * (x - 1).

To find the distance from point P to line m, we can use the formula for the distance between a point and a line.

The formula is:

distance = |Ax + By + C| / sqrt(A^2 + B^2),

where A, B, and C are the coefficients of the equation of the line, and (x, y) is a point on the line. In this case, the equation of line m is y = mx, where m = 1.

So, A = -1, B = 1, and C = 0. Plugging in the values for point P, we get:

distance = |(-1)(1) + (1)(2) + (0)| / sqrt((-1)^2 + 1^2) = |1 + 2 + 0| / sqrt(1 + 1) = 3 / sqrt(2).

Therefore, the distance from point P to line m is 3 / sqrt(2).

User Beethoventhepoet
by
7.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories