Final answer:
There are0.398 mol moles of He in the 5.00 L tank.
Step-by-step explanation:
To calculate the moles of He in the tank, we can use the ideal gas law equation: PV = nRT.
Rearranging the equation to solve for n, we have n = PV/RT.
Plugging in the given values:
V = 5.00 L,
P = 2.80 atm,
T = 155°C + 273 = 428 K,
R = 0.0821 L·atm/(mol·K), we can calculate the moles of He:
n = PV/RT.
n = (2.80 atm)(5.00 L) / (0.0821 L·atm/(mol·K) * 428 K) = 0.398 mol
Therefore, there are0.398 mol moles of He in the 5.00 L tank.
Your full question was
How many moles of He are contained in a 5.00 L tank at 155°C and 2.80 atm?