Question

What is the combustion reaction of 2.2 dimethylpropane:

a. C5 H12 + 802 --> 5CO2
b.C3H8 +502 -->3CO2
c. C5H12 + O2 ---> 5C0
d. C3H8 + 02 -- + 6H20 + 4H20 + 6 H20 >CO2 + H20

Answer 1

The combustion reaction of 2,2-dimethylpropane is C5H12 + 8O2 → 5CO2 + 6H2O, where it reacts with oxygen to produce carbon dioxide and water.

Step-by-step explanation:

The combustion reaction of 2,2-dimethylpropane (C5H12) involves its reaction with molecular oxygen (O2) to form carbon dioxide (CO2) and water (H2O) as products. An example of a balanced combustion reaction is the combustion of propane (C3H8), which is shown in the equation: C3H8 + 5O2 → 3CO2 + 4H2O. Therefore, the correct combustion reaction for 2,2-dimethylpropane, which follows a similar pattern, would be: C5H12 + 8O2 → 5CO2 + 6H2O. The equation shows that one molecule of 2,2-dimethylpropane reacts with eight molecules of oxygen to produce five molecules of carbon dioxide and six molecules of water.