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The equation 3x + 2 = 2√(2x + 4√2) has the solution:

a) x = 8√2 - 10
b) x = 3 - 2/2
c) x = 8√2 + 10

1 Answer

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Final answer:

To solve the equation 3x + 2 = 2√(2x + 4√2), we can eliminate the square root by squaring both sides. By expanding and simplifying the equation, we can then solve it as a quadratic equation using the quadratic formula.

Step-by-step explanation:

The given equation is 3x + 2 = 2√(2x + 4√2). To solve for x, we need to isolate x on one side of the equation. Let's start by squaring both sides of the equation to eliminate the square root:

(3x + 2)² = (2√(2x + 4√2))²

Expanding the left side, we get:

9x² + 12x + 4 = 8(2x + 4√2)

Now, distribute the 8 on the right side:

9x² + 12x + 4 = 16x + 32√2

Combine like terms and isolate the radical term:

9x² - 4x - 16x - 32√2 + 4 = 0

9x² - 20x - 32√2 + 4 = 0

This is a quadratic equation. We can solve it by factoring, completing the square, or using the quadratic formula. In this case, let's use the quadratic formula:

x = (-(-20) ± √((-20)² - 4(9)(-32√2 + 4))) / (2(9))

x = (20 ± √(400 + 1152√2 - 144)) / 18

Simplifying under the square root:

x = (20 ± √(400 + 1152√2 - 144)) / 18

x = (20 ± √256 + 1152√2) / 18

x = (20 ± (16 + 1152√2)) / 18

The answer is x = (20 + (16 + 1152√2)) / 18 or x = (20 - (16 + 1152√2)) / 18.

User Steffan Harris
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