Final answer:
The mass of 20.0 cm³ of carbon tetrachloride is 31.9 grams. The density of a liquid with a specific gravity of 0.50 is 0.50 g/cm³. The specific volume in cm³/g for a liquid with a density of 0.50 g/cm³ is 2 cm³/g.
Step-by-step explanation:
In order to find the mass of carbon tetrachloride, we can use the formula density = mass/volume. For the given problem, the density of carbon tetrachloride is 1.595 g/cm³ and the volume is 20.0 cm³. Plugging in these values, we get mass = 1.595 g/cm³ * 20.0 cm³ = 31.9 grams. Therefore, the mass of 20.0 cm³ of carbon tetrachloride is 31.9 grams.
To find the density in g/cm³ for a liquid with a specific gravity of 0.50, we can use the formula density = specific gravity * water density. Density of water is approximately 1 g/cm³. Plugging in the values, we get density = 0.50 * 1 g/cm³ = 0.50 g/cm³.
The specific volume can be calculated by taking the reciprocal of the density. So, the specific volume in cm³/g for a liquid with a density of 0.50 g/cm³ would be 1/0.50 = 2 cm³/g.
To convert density to lb/ft³, we can use the conversion factor 1 lb/ft³ = 16.018463 g/cm³. For example, if the density in g/cm³ is 1.595 g/cm³, the density in lb/ft³ would be 1.595 g/cm³ * 16.018463 lb/ft³/g/cm³ = 25.55 lb/ft³.
If the density is 0.50 g/cm³ and the volume is 30.0 cm³, the mass would be 0.50 g/cm³ * 30.0 cm³ = 15.0 grams.
To find the volume occupied by 18 grams of the liquid, we can use the formula volume = mass / density. If the mass is 18 grams and the density is 0.50 g/cm³, the volume would be 18 grams / 0.50 g/cm³ = 36 cm³.