Question

If a translation of T(−3,−8) is applied to square ABCD, what is the y-coordinate of B'?

A) 0 - 12
B) 0 - 8
C) 0 - 6
D) 0 - 2

Answer 1

After applying translation T(-3,-8) to square ABCD, the y-coordinate of B' is the original y-coordinate of B minus 8. Assuming B's y-coordinate is 0, B' would have a y-coordinate of 8.

Step-by-step explanation:

If a translation of T(-3,-8) is applied to square ABCD, to find the y-coordinate of B', we simply subtract 8 from the original y-coordinate of point B. Since we have not been given the specific coordinates of B, we will assume it has a y-coordinate of 0 (if it lies on the x-axis, for example). Applying the translation:

y-coordinate of B' = y-coordinate of B - translation in y

y-coordinate of B' = 0 - (-8)

y-coordinate of B' = 0 + 8

y-coordinate of B' = 8

Thus, the answer would be option B) 0 - 8, which simplifies to positive 8.