Final answer:
To make a 325 mL solution with a concentration of 2.76 M from a 3.95 M solution of potassium chloride (KCl), you would need approximately 225.99 mL of the 3.95 M solution.
Step-by-step explanation:
To determine the volume of the 3.95 M potassium chloride (KCl) solution needed to make 325 mL of a 2.76 M solution by dilution, we can use the formula:
C1V1 = C2V2
where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.
Plugging in the values we have:
(3.95 M)(V1) = (2.76 M)(325 mL)
V1 = (2.76 M)(325 mL) / (3.95 M)
V1 = 225.99 mL
Therefore, the volume of the 3.95 M potassium chloride solution needed to make 325 mL of a 2.76 M solution by dilution is approximately 225.99 mL.