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All students in a class practice at least one of the following extracurricular activities: swimming and dancing, Three-fifths of the class's students practice swimming and three-fifths of students practice dance. Five students practice both extracurricular activities. How many students does the class have?​

User Carlita
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Final answer:

To find the total number of students in the class who practice swimming and dancing, we use the principle of inclusion-exclusion. The equation based on the given fractions of students participating in each activity and those participating in both leads us to conclude that the class has 25 students.

Step-by-step explanation:

The question involves solving a problem related to extracurricular activities among the students in a class. To find out the number of students in the class, we can use the principle of inclusion-exclusion. As per the problem statement:

  • Three-fifths of the class practices swimming.
  • Three-fifths of the class practices dance.
  • Five students practice both activities.

Let n be the total number of students in the class. Then, the number of students practicing each activity is (3/5)n, and the sum of the students practicing either swimming or dancing is 2*(3/5)n, but this double counts the students who do both. Therefore, we subtract the five students who do both to avoid double counting:

Total number of students = (3/5)n + (3/5)n - 5

However, since every student does at least one activity, the total number in this equation is just n. So,

n = (3/5)n + (3/5)n - 5

Simplifying the equation,

n = (6/5)n - 5

5 = (1/5)n

Therefore, n = 25. So, the class has 25 students.

User Sonichy
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