66.2k views
5 votes
What can you say about the y-values of the two functions f(x) = 3x² - 3 and g(x) = 2ˣ - 3?

User Socasanta
by
8.4k points

1 Answer

2 votes

Final Answer:

The y-values of the two functions f(x) = 3x² - 3 and g(x) = 2ˣ - 3 differ significantly due to their distinct algebraic forms and behaviors.

Step-by-step explanation:

Firstly, let's analyze the function f(x) = 3x² - 3. This is a quadratic function, and the leading coefficient (3) indicates that the parabola opens upwards. The constant term (-3) shifts the parabola downward by three units. Thus, for any given x-value, the corresponding y-value will be the result of squaring x, multiplying by 3, and then subtracting 3.

Now, consider the function g(x) = 2ˣ - 3. This is an exponential function with a base of 2. Exponential functions grow (or decay) at a rate proportional to their current value. In this case, the term 2ˣ grows rapidly as x increases. The constant term (-3) shifts the entire graph downward by three units. Consequently, the y-values for g(x) will increase exponentially with increasing x.

In summary, while f(x) = 3x² - 3 represents a quadratic relationship resulting in a parabolic curve, g(x) = 2ˣ - 3 signifies exponential growth with a base of 2. The y-values of these functions diverge as they respond differently to changes in the input variable x, reflecting the distinctive characteristics of quadratic and exponential functions.

User Igor Lantushenko
by
7.9k points