Final answer:
The calculation of nuclear binding energy for calcium-40 (40Ca) requires the use of mass defect and mass-energy equivalence concepts, but due to missing mass details for protons and neutrons, the precise value cannot be calculated with the information provided.
Step-by-step explanation:
The question pertains to the calculation of the nuclear binding energy for calcium-40 (40Ca). This involves the concept known as mass defect, which is the difference between the mass of an assembled nucleus and the sum of the masses of its individual nucleons.
By using the provided atomic masses of calcium-40, hydrogen (1H), and neutron (In), we can calculate this difference. The mass defect is converted to energy through the mass-energy equivalence equation, E=mc2, and the use of conversion factors such as 1 amu equals 931 MeV (megaelectronvolts) or its equivalent in joules.
To provide the answer, the mass of the nucleus would be compared to the masses of its constituent protons and neutrons to find the mass defect. Then, this mass defect is multiplied by the conversion factor to find the nuclear binding energy in MeV, which can then be converted to kJ/mole.
However, necessary mass details for protons and neutrons in the given sample are missing, so we cannot calculate the exact nuclear binding energy for 40Ca in this instance.