Final Answers:
(A) Maximum revenue is $680,000 at x = 3000.
(B) Maximum profit of $490,000 at x = 2500. Price should be $125 per set.
(C) With the tax, produce 2000 sets for $100 profit per set at $150 price.
Step-by-step explanation:
For part A, revenue (R) is found by multiplying the quantity sold (x) by the price (p(x)). The price-demand equation p(x) = 200 - x/30 gives the price at a given quantity. Maximizing R, we find x that maximizes p(x) * x, resulting in $680,000 when x = 3000.
Part B requires finding the profit equation, which subtracts the cost function C(x) from the revenue equation. Maximize this profit function to find the production level for maximum profit. The optimal production level is x = 2500, yielding a maximum profit of $490,000. To find the price, substitute x = 2500 into the price-demand equation, p(x) = 200 - x/30, resulting in a price of $125 per set.
In part C, with a $5 tax per set, the cost equation becomes C(x) = 75,000 + 65x. Follow the same steps to maximize profit but with the adjusted cost function. The new optimal production level is x = 2000, yielding a maximum profit of $100 per set at a price of $150.