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Complete the recursive formula of g(n) g(n)= 80(3/4)^2 g(1)=______ g(n)=g(n-1) x _______

User Daley
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Final answer:

To complete the recursive formula of g(n), g(1) is calculated as 60 by substituting n with 1 into the given function. The missing factor to multiply g(n-1) to get g(n) is identified as (3/4), resulting in the formula g(n) = g(n-1) × (3/4).

Step-by-step explanation:

The question involves completing a recursive formula for a function g(n). Given the initial term of the sequence and the common ratio, we can find the missing parts of the formula.

The recursive function is given as g(n) = 80(3/4)^n and g(1) needs to be calculated. The formula also needs a factor to multiply g(n-1) to get g(n).

First, to find g(1), we simply substitute n with 1 into the function:

g(1) = 80(3/4)^1 = 80 * 3/4 = 60

Next, we can identify that the function multiplies each term by (3/4) to get the next term. Therefore, the missing part for multiplying g(n-1) is (3/4).

So, the complete recursive formula is:

  • g(1) = 60
  • g(n) = g(n-1) × (3/4)

User Richard Watson
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