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A 5 N force pushes on the right side of a box. At the same time, a 10 N force pushes on the left side of the box. What happens to the box?

Newton's Third Law
A. The forces pushing on both sides cause it to remain at rest.
B. It is moved to the right by the 10 N force.
C. It is moved to the right by a combined force of 15 N.
D. It is moved to the right by a net force of 5 N.

User Aknay
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Final answer:

The box is subject to a net force of 5 N to the left, as the larger 10 N force applied to the left side of the box overcomes the 5 N force applied to the right side.

Step-by-step explanation:

When a 5 N force pushes on the right side of a box and a 10 N force pushes on the left side, we need to consider the net force acting on the box to determine its motion. According to Newton's Third Law of Motion, forces exist in pairs that are equal in magnitude and opposite in direction. However, the scenario described does not directly pertain to Newton's Third Law but rather to the concept of net force. To find the net force, we subtract the two forces since they are acting in opposite directions.

This results in a net force of 5 N to the left, because the 10 N force is larger and it is applied in the opposite direction to the 5 N force. Therefore, the box will move to the left with a net force of 5 N, not to the right, making the correct answer 'It is moved to the right by a net force of 5 N' incorrect in its direction. The correct answer would imply motion to the left due to the larger force being on that side.

User Amir Jalilifard
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