Final answer:
To find the acceleration of a cheetah that goes from rest to 72 km/h in 2 seconds, convert the velocity to meters per second (72 km/h is 20 m/s), and use the formula a = Δv / Δt. The acceleration is 10 m/s². Therefore the correct answer is c. 72 km/h².
Step-by-step explanation:
The question you are asking about is how to calculate the acceleration of a cheetah that goes from rest to a velocity of 72 km/h in 2 seconds. Acceleration can be calculated using the formula a = Δv / Δt, where 'a' is the acceleration, Δv is the change in velocity, and Δt is the change in time.
First, we need to convert the velocity from kilometers per hour to meters per second by multiplying with (1000/3600), as there are 1000 meters in a kilometer and 3600 seconds in an hour. This gives us 72 km/h * (1000/3600) = 20 m/s. Now, since the cheetah starts from rest, the change in velocity, Δv, is just the final velocity, which is 20 m/s.
Since the time, Δt, is given as 2 seconds, we can plug these numbers into the formula to find the acceleration: a = 20 m/s / 2 s = 10 m/s². This is the cheetah's acceleration.