Question

What’s the integral approximation of t⁶ and m⁶ for ∫(a 2 below the 7) x⁵dx.

Answer 1

The integral approximation of t⁶ and m⁶ for the given integral ∫(a 2 below the 7) x⁵dx is (t^7)/7 + C and (m^7)/7 + C respectively.

Step-by-step explanation:

To find the integral approximation of t⁶ and m⁶ for the given integral, we can use the power rule of integration. According to the power rule, the integral of x^n dx equals (x^(n+1))/(n+1) + C, where C is the constant of integration.

For t⁶, the integral becomes (∫ t⁶ dx) = (t^(6+1))/(6+1) + C = (t^7)/7 + C. Similarly, for m⁶, the integral becomes (∫ m⁶ dx) = (m^(6+1))/(6+1) + C = (m^7)/7 + C.