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A. 62 mL of vinegar to neutralized 85 mL of NaOH.

User Atharva
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Final answer:

This question is about neutralization reactions in Chemistry, specifically calculating the volume of vinegar required to neutralize a given volume of NaOH. We can use the balanced equation and the molar ratio to find the answer.

Step-by-step explanation:

This question is related to the concept of neutralization reactions in Chemistry. Neutralization is a chemical reaction between an acid and a base that results in the formation of a salt and water. In this case, the question is asking about the volume of vinegar (acetic acid) required to neutralize a given volume of NaOH (sodium hydroxide).

To solve this, we need to consider the balanced equation for the neutralization reaction between acetic acid and sodium hydroxide:

CH3COOH + NaOH → CH3COONa + H2O

From the equation, we can see that the molar ratio between acetic acid and NaOH is 1:1. We can use this information to calculate the amount of acetic acid in moles:

moles of acetic acid = moles of NaOH

We can then use the molar volume to convert the moles of acetic acid to mL:

volume of acetic acid = moles of acetic acid * molar volume

By substituting the given values into the equation, we can find the volume of vinegar required to neutralize a given volume of NaOH.

User Andrewgazelka
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