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A conductor of length 2m carries a current of 0.8A while kept in a magnetic field with magnetic flux density 0.5 T. The maximum force acting on it is: A. 0.4N B. 1.6N C. 0.2N D. 0.8N

User Abrown
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Final answer:

The maximum force on a conductor carrying a current in a magnetic field is determined by the equation F = I * L * B * sin(θ). Substituting the provided values, the maximum force is calculated to be 0.8 N, with the correct option being D.

Step-by-step explanation:

The question revolves around calculating the maximum force exerted on a conductor carrying a current within a magnetic field. This is a classical physics problem involving the interaction of electricity and magnetism, specifically the Lorentz force on a current-carrying conductor. The equation to determine the force (F) on a wire with current (I) in a magnetic field is given by F = I * L * B * sin(θ), where L is the length of the wire, B is the magnetic flux density, and θ is the angle between the wire and the magnetic field. Since the problem asks for the maximum force, we assume that sin(θ) is equal to 1 (θ=90°), which allows the wire to experience the greatest force.

Substituting the given values, we have:
F = 0.8 A * 2 m * 0.5 T * sin(90°)
F = 0.8 N

Thus, the maximum force acting on the conductor is 0.8 N. The correct option is D.

User Mandeep Gill
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