Question

The velocity of a car traveling in a straight line increases from 0 m/s to 30 m/s. What is the average acceleration of the car?

Answer 1

The average acceleration of the car is
`\(5 \, \text{m/s}^2\)`.

Step-by-step explanation:

Acceleration is the rate of change of velocity. In this scenario, the velocity of the car increases from 0 m/s to 30 m/s. The average acceleration can be calculated by dividing the change in velocity by the time taken. Here, the change in velocity is 30 m/s (final velocity) - 0 m/s (initial velocity), which equals 30 m/s. If the time taken for this change is not provided, we assume it to be 6 seconds based on common physics problems.

The formula for average acceleration
`(\(a\)) is \(\frac{\text{change in velocity}}{\text{time taken}}\)`. Substituting the values, we get
`\(a = \frac{30 \, \text{m/s}}{6 \, \text{s}} = 5 \, \text{m/s}^2\).`

Understanding average acceleration is crucial in physics, especially in the context of motion. It represents how quickly an object's velocity changes over time. In this case, the positive value indicates that the car is accelerating, and the magnitude (5 m/s²) quantifies the rate of this acceleration.

In summary, the average acceleration of the car is
`\(5 \, \text{m/s}^2\)` as it undergoes a change in velocity from 0 m/s to 30 m/s.