Question

F(x)=x 1
_____
x²+3x+2

Answer 1

When
`\( x = -4 \) for \( f(x) = (x)/(x^2 + 3x + 2) \),` the function evaluates to
`\((-2)/(3)\).` Thus,
`\( f(-4) = (-2)/(3) \).`

To find the value of
`\( f(x) \)`when
`\( x = -4 \)` for the given function
`\( f(x) = (x)/(x^2 + 3x + 2) \)`, substitute
`\( x = -4 \)`into the expression:

`\[ f(-4) = (-4)/((-4)^2 + 3(-4) + 2) \]`

Firstly, evaluate the expression in the denominator:

`\[ (-4)^2 + 3(-4) + 2 = 16 - 12 + 2 = 6 \]`

Now, substitute this value back into the original expression:

`\[ f(-4) = (-4)/(6) \]`

To simplify further, we can divide both the numerator and the denominator by their greatest common divisor, which is 2:

`\[ f(-4) = (-2)/(3) \]`

So, when
`\( x = -4 \)`, the function
`\( f(x) \)` evaluates to
`\( (-2)/(3) \).` Therefore, the answer to the question is that the value of
`\( f(x) \)` when
`\( x = -4 \)` for the given function is
`\( (-2)/(3) \).`

This process demonstrates how to use the provided function to compute specific values, in this case, when
`\( x = -4 \).`

The probable question maybe:

What is the value of
`\( f(x) \) when \( x = -4 \) for the function \( f(x) = (x)/(x^2 + 3x + 2) \)?`