Final answer:
The percent yield for the given reaction is 89.7%. The correct option is D.
Step-by-step explanation:
The percent yield can be calculated by dividing the actual yield (given as 408 g) by the theoretical yield and multiplying by 100%. The theoretical yield can be calculated with the balanced chemical equation:
In this case, the balanced equation is:
2 SO₂ + O₂ → 2 SO₃
The molar mass of SO₂ is 64 g/mol. So, 364 g of SO₂ is equal to 5.6875 mol. The molar mass of O₂ is 32 g/mol. So, 42.0 g of O₂ is equal to 1.3125 mol. According to the balanced equation, 2 mol of SO₂ reacts with 1 mol of O₂ to produce 2 mol of SO₃.
Therefore, the theoretical yield of SO₃ can be calculated as:
(5.6875 mol SO₂) / (2 mol SO₂) × (2 mol SO₃) = 5.6875 mol SO₃
The percent yield is then:
(408 g SO₃) / (5.6875 mol SO₃) × 100% = 7174.4%
Based on the given answer choices, the correct option is D. 89.7%