Question

Select each ordered pair that is a solution of -3x + 5y > -10.

A) (-3, 2)
B) (5, 1)
C) (-2, -1)
D) (0, 3)
There could be many solutions.

Answer 1

The ordered pairs (-3, 2), (-2, -1), and (0, 3) are solutions of the inequality -3x + 5y > -10. Therefore, the ordered pairs that are solutions of the inequality -3x + 5y > -10 are A) (-3, 2), C) (-2, -1), and D) (0, 3).

Step-by-step explanation:

Solution: To determine which ordered pairs are solutions of the inequality -3x + 5y > -10, we can substitute the x and y values into the inequality and check if the inequality is true or false. Let's examine each option:

1. Option A: (-3, 2)
   -3(-3) + 5(2) = 9 + 10 = 19 > -10. Since 19 is greater than -10, this pair is a solution.
2. Option B: (5, 1)
   -3(5) + 5(1) = -15 + 5 = -10 > -10. Since -10 is not greater than -10, this pair is not a solution.
3. Option C: (-2, -1)
   -3(-2) + 5(-1) = 6 - 5 = 1 > -10. Since 1 is greater than -10, this pair is a solution.
4. Option D: (0, 3)
   -3(0) + 5(3) = 0 + 15 = 15 > -10. Since 15 is greater than -10, this pair is a solution.

Therefore, the ordered pairs that are solutions of the inequality -3x + 5y > -10 are A) (-3, 2), C) (-2, -1), and D) (0, 3).