Final answer:
The number of terms in the arithmetic progression is 2 when the common difference is 549.
Step-by-step explanation:
The formula to find the number of terms in an arithmetic progression (AP) is:
n = (last term - first term) / common difference + 1
Given that the first term is 1, the last term is 121, and the common difference is A, we can substitute those values into the formula:
n = (121 - 1) / A + 1
Therefore, the number of terms in the AP with a common difference of A is (120/A) + 1.
So, to find the number of terms, divide 120 by each of the answer options and add 1:
A) (120/549) + 1 = 1.218 + 1 ≈ 2.218 ≈ 2
B) (120/671) + 1 = 0.179 + 1 ≈ 1.179 ≈ 1
C) (120/976) + 1 = 0.123 + 1 ≈ 1.123 ≈ 1
D) (120/1281) + 1 = 0.094 + 1 ≈ 1.094 ≈ 1
Therefore, the correct answer is A) 549, which results in 2 terms in the arithmetic progression.