Final answer:
At the cathode of a galvanic cell with aluminum and copper electrodes, the reaction Cu2+(aq) + 2e- -> Cu(s) occurs because copper has a more positive reduction potential than aluminum.
Step-by-step explanation:
The question is asking which reaction occurs at the cathode of a galvanic cell with aluminum and copper electrodes in their respective electrolytes.
In a galvanic cell, the cathode is where reduction takes place. The electrode with the more positive reduction potential will undergo reduction. Since reduction potentials are given as Cu2+ = 0.34 V and Al3+ = -1.68 V, the copper reaction has the more positive reduction potential and will be reduced at the cathode.
The correct reaction that occurs at the cathode thus is:
Cu2+(aq) + 2e- -> Cu(s)
This corresponds to option A and signifies the reduction of Cu2+ ions to copper metal at the cathode of the galvanic cell.