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Given, P(A) = 0.6, P(B) = 0.4, P(A and B) = 0.1 , determine the probability of P(A or B) if the two events are inclusive (use either of the diagrams below to help you).

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Final answer:

The probability of event A or B occurring, when events are inclusive and given P(A) = 0.6, P(B) = 0.4, and P(A AND B) = 0.1, is 0.9.

Step-by-step explanation:

You are asked to determine the probability of P(A OR B) given that P(A) = 0.6, P(B) = 0.4, and P(A AND B) = 0.1.

The events are inclusive, which means they are not mutually exclusive and can happen at the same time.

The formula to use for inclusive events is:

P(A OR B) = P(A) + P(B) − P(A AND B).

Plugging in the values you provided:

P(A OR B) = 0.6 + 0.4 − 0.1 = 0.9

The probability of event A or B occurring is 0.9.

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