Final answer:
The balanced chemical equation is 2KI (aq) + Pb(NO3)2 (aq) → 2KNO3 (aq) + PbI2 (s), resulting in a yellow precipitate of PbI2 and soluble KNO3.
Step-by-step explanation:
The balanced chemical equation for the reaction between potassium iodide (KI) and lead(II) nitrate (Pb(NO3)2) is:
2KI (aq) + Pb(NO3)2 (aq) → 2KNO3 (aq) + PbI2 (s)
This reaction results in the formation of lead(II) iodide (PbI2), which is a brilliant yellow precipitate due to the strong attractive forces between Pb²⁺ and I⁻ ions. Potassium nitrate (KNO₃) is the other product of this reaction, and it remains soluble in the aqueous solution.