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A car accelerates at 2m/sec^2 for 16 seconds and they maintain a constant speed for 16 more seconds. What is the total distance traveled?

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Final answer:

The total distance traveled by the car is 384 meters.

Step-by-step explanation:

To find the total distance traveled, we need to calculate the distance covered during the acceleration phase and the distance covered during the constant speed phase.

During the acceleration phase, the car accelerates at a rate of 2m/sec^2 for 16 seconds. Using the equation d = (1/2)at^2, we can calculate the distance covered during this phase:
d = (1/2) * 2 * (16)^2 = 256 meters

During the constant speed phase, the car maintains a constant speed. The distance covered during this phase can be calculated using the equation d = v * t, where v is the constant speed and t is the time:
d = 8 m/s * 16 s = 128 meters

Therefore, the total distance traveled by the car is 256 meters + 128 meters = 384 meters.

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