Final answer:
The question is a mathematical problem about finding a 3-digit number less than 130, where the sum of the ones and hundreds place digits equals the tens place digit. By understanding the place value of digits, we can determine that the number is between 110 and 129. Key to solving this problem is realizing the hundreds place is '1', and the ones place can vary to satisfy the given condition.
Step-by-step explanation:
The subject of this question is Mathematics, specifically dealing with the place value of a number and significant figures. To determine a 3-digit number less than 130 that satisfies the condition where the addition of the ones and hundreds place digits equals the tens place digit, one must understand the place value system. In the place value system, digits represent different values depending on their position relative to the decimal point. For instance, in the number 231.45, '2' is in the hundreds place, '3' is in the tens place, and '1' is in the ones place.
For the given condition, the tens place digit has to be the sum of the hundreds and ones place digits. Since the number is less than 130, the hundreds place can only be '1', and the tens place necessarily has to be a single-digit number. If we use 'x' for the ones place and 'y' for the tens place, then the equation becomes: 1 + x = y. The highest value for 'x' could be 8 since the number must remain a 3-digit number, which would make 'y' equal to 9 (for example, 198).