Question

For a given cylindrical motor, the acting force (F = 50 N). The moment of inertia (I = 1/8 rad/s²). The angular acceleration will be:

a) (100 rad/s²)

b) (10 rad/s²)

c) (50 rad/s²)

d) (150 rad/s²)

Answer 1

The angular acceleration for the given cylindrical motor is 6.67 rad/s².

Step-by-step explanation:

To solve for the angular acceleration, we can use the equation:

a = Στ / I

where a is the angular acceleration, Στ is the torque, and I is the moment of inertia.

In this case, the torque is 375 N·m and the moment of inertia is 56.25 kg·m². Plugging in these values, we find:

a = 375 N·m / 56.25 kg·m² = 6.67 rad/s²

Therefore, the angular acceleration is (c) 6.67 rad/s².