Question

Use the periodic table to determine the amount of copper and aluminum nitrate formed in the reaction.

In the reaction,

moles of Cu and

moles of Al(NO₃)₃ are formed.

Express your answer to the correct number of significant figures.

A. 1 mole of Cu, 2 moles of Al(NO₃)₃
B. 2 moles of Cu, 1 mole of Al(NO₃)₃
C. 1 mole of Cu, 1 mole of Al(NO₃)₃
D. 2 moles of Cu, 2 moles of Al(NO₃)₃

Answer 1

The reaction of copper with silver nitrate produces 1 mole of Cu and 2 moles of Al(NO₃)₃ according to the stoichiometry of the provided chemical equation.

The correct amount of copper and aluminum nitrate formed is option A: 1 mole of Cu, 2 moles of Al(NO₃)₃.

Step-by-step explanation:

When examining the stoichiometry of the reaction between copper and silver nitrate, it's clear that the coefficients indicated in the chemical equation must represent the molar ratios of the reactants and products involved in the reaction.

The provided equation, Cu (s) + 2AgNO₃(aq) → Cu(NO₃)₂ (aq) + 2Ag (s), shows that one mole of solid copper reacts with two moles of aqueous silver nitrate to produce one mole of aqueous copper (II) nitrate and two atoms of solid silver.

Therefore, the correct amount of copper and aluminum nitrate formed is option A: 1 mole of Cu, 2 moles of Al(NO₃)₃.