Final answer:
The heat produced in the neutralization reaction of 0.05 moles of HCl and 0.05 moles of NaOH is closely estimated to be approximately 2.8 kJ, based on a similar example provided.
Step-by-step explanation:
The question is about calculating the heat produced during the neutralization reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH). This type of reaction is exothermic, meaning it releases heat. Since we have an equal volume and molarity of HCl and NaOH, we can determine the moles of each reactant, which are also equal. Each has 0.05 moles given that both solutions have a volume of 50.0 mL and a molarity of 1.00 M. According to the provided examples, we know that the reaction of 0.0500 mol HCl with 0.0500 mol NaOH produces 2.9 kJ of heat.
Since the same amounts of acid and base are used, and the heat produced per 0.0500 mol is given, the total heat produced can be directly taken from the example, which is 2.9 kJ. Therefore, the correct answer to the question would be:
Approximately 2.8 kJ of heat is produced during the reaction, similar to the value given in the example. However, since the temperature rise to 31.1°C in this case is not given in the examples and no specific heat or mass information is provided, we cannot accurately calculate the produced heat for the exact temperature rise without making assumptions. Therefore, we have to select the closest estimate based on similar examples at hand.