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Maya is committing to a plan to read more books. On April 1, she reads 15 pages in a book and plans to increase the number of pages by 3 each day for a month. How many pages will she read on April 30?

User Jaffar
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Final answer:

Maya will read 102 pages on April 30, calculated by using the formula for the nth term of an arithmetic sequence with the first term being 15 pages and the common difference being 3 pages per day.

Step-by-step explanation:

To determine how many pages Maya will read on April 30, we will treat this scenario as an arithmetic sequence. Maya starts by reading 15 pages and increases the number of pages by 3 each day. Since April has 30 days, we need to find the number of pages she will read on the 30th day.

The general formula for the nth term of an arithmetic sequence is a_n = a_1 + (n - 1)d, where a_n is the nth term we want to find, a_1 is the first term, d is the common difference, and n is the nth term. In this case, a_1 = 15 pages, d = 3 pages/day, and n = 30.

Applying the values to the formula, we get a_30 = 15 + (30 - 1)(3) = 15 + 29(3) = 15 + 87 = 102 pages.

Therefore, on April 30, Maya will read 102 pages.

User Mkuff
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