Final answer:
The mass of water needed to react with 64 grams of titanium (II) sulfide cannot be determined without the balanced chemical equation of their reaction. Typically, you would use stoichiometry to calculate moles of TiS and then find the mass of water needed according to the molar ratio.
Step-by-step explanation:
The mass of water required to react with 64 grams of titanium (II) sulfide (TiS) can be calculated using stoichiometry. You would need to know the balanced chemical equation for the reaction between TiS and water to determine the molar ratio of the reactants.
Unfortunately, the reaction details or the balanced equation have not been provided in the question, therefore an accurate answer cannot be supplied without further information. Normally, you would calculate the number of moles of TiS (using its molar mass), then use the molar ratio from the balanced equation to find the moles of water needed.
Finally, you multiply the moles of water by its molar mass (18.02 g/mol) to find the mass required. As the necessary details are absent, it's recommended to seek the balanced chemical equation before making this calculation.