Final answer:
The coverage for a 50 Mb genome using 1 x 10^8 sequences with an average length of 90 bases is 180x.
Step-by-step explanation:
To calculate the coverage of a sequenced genome, you multiply the total number of sequences by the average length of these sequences, and then divide that product by the size of the genome. In the case described, you have 1 x 108 sequences with an average length of 90 bases and are applying this to a 50 Mb (megabase) genome:
Total bases sequenced = 1 x 108 sequences x 90 bases/sequence = 9 x 109 bases
Coverage = Total bases sequenced / Size of Genome in bases
= 9 x 109 bases / 50 x 106 bases
= 180x
Therefore, the coverage obtained from sequencing 1 x 108 sequences with an average length of 90 bases for a 50 Mb genome is 180x.