Question

A) has a slope of 6 and passes through the

point (1, 5).
b) is perpendicular to line (a) and passes
through the point (6,-3).

Answer 1

The equation of line (a) with a slope of 6 passing through the point (1, 5) is y = 6x - 1. The equation of line (b) perpendicular to line (a) passing through the point (6, -3) is y = (-1/6)x + (7/2).

Step-by-step explanation:

To determine the equation of a line, we use the slope-intercept form, which is y = mx + b, where m is the slope and b is the y-intercept.

For part a), the equation of the line with a slope of 6 passing through the point (1, 5) is y = 6x - 1.

For part b), since the given line is perpendicular to line (a), it must have a negative reciprocal slope. Therefore, the equation of the line with a negative reciprocal slope of -1/6 passing through the point (6, -3) is y = (-1/6)x + (7/2).