Question

Write a command that shows all fields from the table "cats" where the name has both an s and an e at some point; s first then e

Answer 1

To find all entries in the 'cats' table with names containing 's' before 'e', use SQL command: SELECT * FROM cats WHERE name LIKE '%s%e%'; The percent signs (%) are wildcards used in the LIKE operator for pattern matching.

Step-by-step explanation:

To write a command that shows all fields from the table "cats" where the name contains both an 's' and an 'e' with 's' coming before 'e', you would use a Structured Query Language (SQL) SELECT statement with a WHERE clause that incorporates pattern matching. The LIKE operator can be used in conjunction with wildcard characters to match this pattern. Here is an example of such a command:

SELECT * FROM cats WHERE name LIKE '%s%e%';

This command selects all records (*) from the table 'cats' where the 'name' field contains an 's' followed by an 'e' at any point thereafter. The percentage signs (%) act as wildcards that allow for any number of characters to appear before, between, and after the 's' and 'e'.