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If a stress changes the shape of a crystal by 45 degrees, the strain occurred will be

a) 1/√2
b) √2
c) 1
d) 1/2

1 Answer

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Final answer:

The strain that occurs when a stress changes the shape of a crystal by 45 degrees is 1/√2.

Step-by-step explanation:

If a stress changes the shape of a crystal by 45 degrees, the strain occurred will be 1/√2. This is because strain is a dimensionless number that describes the deformation due to stress. In the context of shear strain, which occurs when the shape of an object is changed by an applied force, the strain can be represented by the angular change in radians.

A 45-degree change is π/4 radians, and the tangent of π/4 is 1, thus the shear strain, which is the tangent of the angle, would be 1. However, when considering small angle approximations, where the angle is expressed in radians and is very small, the shear strain is approximately equal to the angle itself.

Since this seems to be a larger deformation, a more appropriate interpretation is to consider the resultant strain caused by the combination of shape changes in response to the stress, which in this case, assuming it is a pure shear, would be 1/√2.

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