47.3k views
0 votes
Solve the system of equations:

-3x = -36 + 7y
-3x + 2y = -36

a. x = 4, y = 6
b. x = -4, y = 6
c. x = 4, y = -6
d. x = -4, y = -6

User Magodiez
by
8.2k points

1 Answer

2 votes

Final answer:

To solve the system of equations -3x = -36 + 7y and -3x + 2y = -36, we can use the method of elimination. The equations are identical, which means they represent the same line and have infinitely many solutions.

Step-by-step explanation:

To solve the system of equations -3x = -36 + 7y and -3x + 2y = -36, we can use the method of substitution or elimination. Let's use the method of elimination:

Multiply the second equation by 7 to make the coefficients of y the same:
-3x + 2y = -36 (1)
-21x + 14y = -252 (2)

Now subtract equation (1) from equation (2) to eliminate x:
-21x + 14y - (-3x + 2y) = -252 - (-36)
-21x + 14y + 3x - 2y = -216
-18x + 12y = -216

Divide the equation by 6 to simplify:
-3x + 2y = -36
-3x + 2y = -36

As we can see, the equations are identical. This means that they represent the same line and have infinitely many solutions. Therefore, the correct answer is:

c. x = 4, y = -6

User Swathi Anupuram
by
8.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories