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Derive the system of equations:

2a + b - 3c = 7
4a - 3b + 2c = 12
a + 2b + c = 5

1 Answer

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Final answer:

To derive the given system of equations, we start by rearranging the first equation to solve for a. Then substitute this value of a in the second and third equation. Simplify the equations to obtain the derived system.

Step-by-step explanation:

The given system of equations is:

2a + b - 3c = 7

4a - 3b + 2c = 12

a + 2b + c = 5

To derive this system of equations, we start by rearranging the first equation to solve for a:

a = (7 - b + 3c)/2

Next, we substitute this value of a in the second and third equation:

4[(7 - b + 3c)/2] - 3b + 2c = 12

(7 - b + 3c)/2 + 2b + c = 5

Simplifying these equations, we get:

14 - 2b + 6c - 3b + 2c = 24

7 - b + 3c + 4b + 2c = 10

Combining like terms, we have:

-5b + 8c = 10

3b + 5c = 3

Therefore, the derived system of equations is:

-5b + 8c = 10

3b + 5c = 3

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