Question

A baby elephant's position equation is x(t) = 24 cm + (2.25 cm/s)t – (0.06 cm/5'). Calculate the baby elephant's initial position, velocity, and acceleration.

a) Initial position: 24 cm, Velocity: 2.25 cm/s, Acceleration: -0.06 cm/s²
b) Initial position: 24 cm, Velocity: 2.25 cm/s, Acceleration: 0.06 cm/s²
c) Initial position: 24 cm, Velocity: 0.06 cm/s, Acceleration: -2.25 cm/s²
d) Initial position: 24 cm, Velocity: -2.25 cm/s, Acceleration: 0.06 cm/s²

Answer 1

The initial position of the baby elephant is 24 cm, its initial velocity is 2.25 cm/s, and its acceleration is -0.06 cm/s², which corresponds to option a in the question.

Step-by-step explanation:

The student's question pertains to the physics of motion, specifically to finding the initial position, velocity, and acceleration of a baby elephant from a given position equation x(t) = 24 cm + (2.25 cm/s)t – (0.06 cm/s2)t2. The correct answer to the question is that the initial position is 24 cm, the velocity is 2.25 cm/s, and the acceleration is -0.06 cm/s2 since the coefficients of the equation represent the initial position, velocity, and acceleration respectively.