Answer:
12.5 m/s
Step-by-step explanation:
Your post omits some key assumptions needed to solve it:
I will assume you want the speed of the skier at the BOTTOM of the hill
I will also assume no effect from friction
THEN the skier's POTENTIAL energy (at the top of the hill) = mgh
all of this PE is converted to Kinetic Energy (1/2 mv^2)at the bottom of the hill
mgh = 1/2 mv^2
2gh = v^2
v = sqrt ( 2 g h ) = sqrt ( (2 * 9.81 * 8) = 12.5 m/s
(note that the mass, 50 kg, is irrelevant )