Final answer:
The intensity of sound at 95 dB is 10 times greater than the intensity at 85 dB because a 10 dB increase corresponds to a ten-fold increase in sound intensity.
Step-by-step explanation:
The question asks about the difference in sound intensity levels measured in decibels (dB). To solve this, we know that a 10 dB increase indicates that the intensity of sound is 10 times greater. Thus, to find out how many times greater is the intensity of sound at 95 dB over the intensity of sound at 85 dB, we look at the difference in decibels, which is 95 dB - 85 dB = 10 dB.
Since each 10 dB difference corresponds to a sound intensity 10 times greater, a 10 dB increase means that the sound intensity at 95 dB is 10 times greater than at 85 dB.
Therefore, the correct answer is A. 10 times.