Final answer:
The candidate can make up his choice in 210 different ways. Hence, B) is correct.
Step-by-step explanation:
The candidate is required to answer 6 out of 10 questions divided into two groups.
The number of ways the candidate can make up his choice can be calculated using combinations. In this case, we need to find the number of ways to choose 6 questions out of 10.
The formula for combinations is nCr = n! / (r!(n-r)!), where n is the total number of items and r is the number of items to be chosen.
Plugging in the values, we have 10C6 = 10! / (6!(10-6)!).
Simplifying this expression, we get 10C6 = 10! / (6!4!).
Canceling the common terms, we get 10C6 = (10*9*8*7) / (4*3*2*1).
Evaluating the expression, we have 10C6 = 210.