Final answer:
The stone will be in flight for a certain amount of time before it hits the ground. Using the principle of conservation of energy, we can determine the speed with which the stone strikes the ground by equating the potential energy to the initial kinetic energy. The stone strikes the ground with a speed of 21.6 m/s.
Step-by-step explanation:
The stone will be in flight for a certain amount of time before it hits the ground. To determine this, we can use the principle of conservation of energy. When the stone is dropped from the window, it has potential energy due to its height above the ground. As it falls, this potential energy is converted to kinetic energy. By equating the potential energy to the initial kinetic energy, we can find the speed of the stone when it strikes the ground.
Using the equation for potential energy (PE = mgh) and the fact that the stone is dropped from a height of 6 m, we can find the potential energy to be 14.7 J. Since the stone has negligible air resistance, all the potential energy is converted to kinetic energy. Therefore, the kinetic energy of the stone is also 14.7 J at the moment it hits the ground.
Using the equation for kinetic energy (KE = 0.5mv^2) and the fact that the mass of the stone is 25 g (0.025 kg), we can solve for the velocity (v) of the stone. Rearranging the equation, we get v = sqrt(2KE/m). Substituting the values, we get v = sqrt((2 * 14.7) / 0.025) = 21.6 m/s.
Therefore, the speed with which the stone strikes the ground is 21.6 m/s.