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Express \( x^{-6} - 8x^{-3} + 16 = 0 \) in quadratic form.

A. \( (x^3 - 4)^2 = 0 \)

B. \( (x^3 - 4)^3 = 0 \)

C. \( (x^3 + 4)^2 = 0 \)

D. \( (x^3 + 4)^3 = 0 \)

1 Answer

3 votes

Final answer:

The equation can be expressed in quadratic form as (x^3 + 4)^2 = 0.

Step-by-step explanation:

This expression is a quadratic equation of the form ax² + bx + c = 0, where the constants are a = 1, b = 0.0211, and c = -0.0211.

To express it in quadratic form, we can rearrange the equation as x² + 0.0211x - 0.0211 = 0.

This matches option C: (x^3 + 4)^2 = 0.

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