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Absolute Value Function Vertex Exploration

Find the vertex of the absolute value function provided.

f(x)=∣x+11∣−7

The vertex is located at ________________.

Identify the domain and range of the function.
A) Domain: All real numbers; Range: f(x)≥−7
B) Domain: All real numbers; Range: f(x)≥27
C) Domain: f(x)=1; Range: f(x)≥−7
D) Domain: f(x)=21; Range: All real numbers

User Jkeirstead
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1 Answer

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Final answer:

The vertex of the absolute value function f(x) = |x + 11| - 7 is at the point (-11, -7). The domain is all real numbers and the range is f(x) ≥ -7.

Step-by-step explanation:

The vertex of an absolute value function, which has a general form of f(x) = |ax + b| + c, occurs at the point where the expression inside the absolute value is zero. For the given function f(x) = |x + 11| - 7, we set the expression within the absolute value to zero and solve for x which gives us x = -11. Thus, the vertex is located at (-11, -7).

The domain of an absolute value function is the set of all real numbers, because there are no restrictions on the values that x can take. The range of this function is the set of all real numbers y such that f(x) ≥ -7, because the lowest point on the graph of the function is the vertex and the value of the function never decreases below the y-coordinate of the vertex (-7). Therefore, the function increases above -7 for all other x values.

So the correct domain and range for the function f(x) = |x + 11| - 7 are:

  • Domain: All real numbers
  • Range: f(x) ≥ -7

The correct answer to the student's question is:

The vertex is located at (-11, -7).

Identify the domain and range of the function:

A) Domain: All real numbers; Range: f(x) ≥ -7

User Dan Jaouen
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