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What is the equation, in point-slope form, of the line that is parallel to the line represented by y - 1 = -(x + 3) and passes through the point (-3, 1)?

A. y - 1 = -(x + 3)
B. y - 1 = (x + 3)
C. y - 1 = - (x - 3)
D. y - 1 = (x - 3)

User M Omayr
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Final answer:

The equation, in point-slope form, of the line that is parallel to y - 1 = -(x + 3) and passes through the point (-3, 1) is y - 1 = -(x + 3).

Step-by-step explanation:

To find the equation of the line that is parallel to the line represented by y - 1 = -(x + 3) and passes through the point (-3, 1), we need to determine the slope.

The given equation is already in point-slope form, where y - y1 = m(x - x1). From the given equation, the slope is -1.

Since a line parallel to another line has the same slope, the equation of the line parallel to y - 1 = -(x + 3) will also have a slope of -1.

Thus, the equation of the line can be written as y - 1 = -1(x - (-3)), which simplifies to y - 1 = -(x + 3).

User S Rivero
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