Final answer:
The question addresses how the attendance of a science convention changes annually from the initial 2014 count with given increase, decrease, and constant rate options. To illustrate these concepts, if attendance doubles each year, starting from an initial 1,000, it would be 2,000 in the second year, 4,000 in the third, and so on. Conversely, a decrease by 11% annually would multiply the previous year's attendance by 0.89 for each subsequent year. So, the correct option is B. Decreases by 11% each year
Step-by-step explanation:
The question posed relates to how the attendance at a science convention changes annually from the initial count in 2014, presenting several options such as an annual increase by 11%, a decrease by 11%, remaining constant, or doubling every year.
To tackle the question with the information provided, we can examine various rates of change and how they affect the initial count, such as doubling or decreasing in value.
To clarify this concept with an example, let's say the initial count of attendance in 2014 was 1,000 attendees.
If the attendance doubles every year, it would look like this:
Year 2015: 1,000 x 2 = 2,000 attendees
Year 2016: 2,000 x 2 = 4,000 attendees
Year 2017: 4,000 x 2 = 8,000 attendees
On the other hand, if the attendance were to decrease by 11% each year, starting again with 1,000 attendees in 2014, we would calculate the new attendance by multiplying by 0.89 (which is 100% - 11%) each year.
Neither increasing fourfold, sixfold, nor remaining unchanged are mentioned in the initial options provided in the schedule question. Therefore these particular rates of change are not directly relevant to the scenario at hand.
However, understanding these various multipliers can help students grasp the concept of exponential growth and decay, which are common in calculations involving population, finance, and indeed convention attendance modeling.
So, the correct option is B. Decreases by 11% each year