Question

How many joules of energy are needed to raise the temperature of 250 grams of water from 45°C to 85°C? The specific heat for liquid water is C= 4.18 J/g°C. a. 4180 J

b. 1045 J
c. 836 J
d. 627 J

Answer 1

The amount of energy needed to raise the temperature of 250 grams of water from 45°C to 85°C can be calculated using the formula Q = mcΔT, where Q is the heat energy, m is the mass, c is the specific heat, and ΔT is the change in temperature. The correct answer is (a) 4180 J.

Step-by-step explanation:

Using the formula Q = mcΔT:

Q = (250 g) × (4.18 J/g°C) × (85°C - 45°C)

Q = 250 g × 4.18 J/g°C × 40°C

Q = 4180 J

Therefore, the correct answer is (a) 4180 J. This represents the amount of energy required to raise the temperature of 250 grams of water from 45°C to 85°C.