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Two sides of a parallelogram meet at an angle of 42 degrees. If the length of one side is 10 inches and the other side is 14 inches, what is the length of the shortest diagonal of the parallelogram?

a.9.18 inches
b.8.15 inches
c.10.32 inches
d.7.45 inches

1 Answer

5 votes

Final answer:

To determine the length of the shortest diagonal in a parallelogram, one can use the Law of Cosines with the given side lengths and the angle between them. However, the calculation indicated that none of the answer choices provided are correct, suggesting a potential error in the question's options.

Step-by-step explanation:

To find the length of the shortest diagonal of the parallelogram, we can use the Law of Cosines. The parallelogram sides are 10 inches and 14 inches, which meet at a 42-degree angle. The Law of Cosines, which relates the sides of a triangle with the cosine of one of its angles, states in this context that: c² = a² + b² - 2ab*cos(C), where 'c' is the length of the diagonal, 'a' and 'b' are the lengths of the adjacent sides, and 'C' is the angle between them.

Let's plug in the values: c² = 10² + 14² - 2*(10)*(14)*cos(42°). After performing the calculations, we find the length of the shortest diagonal 'c'. When you carry out the calculations, none of the provided options in the student question are correct so we cannot select a valid choice from options a, b, c, or d. Therefore, it seems that there might be a mistake in the options provided in the question or in the application of the formula. Without the correct computation, it's not possible to confidently provide an exact answer.

User Mauro Gentile
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